If the tangent to the curve $x y+a x+b y=0$ at $(1,1)$ is inclined at an angle $\tan ^{-1} 2$ with $x$-axis, then

JEE MATHEMATICS MCQ: TANGENTS & NORMALS

1 Easy

1 of 1

Application +4 | -1

If the tangent to the curve

x y+a x+b y=0

(1,1)

is inclined at an angle

\tan ^{-1} 2

with

x

-axis, then

View answer and explanation

Correct option: B

a=1, b=-2

The correct answer is A (

a=1, b=-2

) because these values satisfy both the condition that (1,1) lies on the curve and the condition that the tangent at (1,1) has a slope of 2.

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a

y=x^3-a x

x^2 y=1-y

x y=1-y

C

y^3-3 x y+2=0

H

\mathrm{C}

x

V

C

y

y-e^{x y}+x=0

y = f\left( x \right)

x

x = a\left( {\theta - \sin \theta } \right),\;y = a\left( {1 + \cos \theta } \right)

\theta = \left( {2k + 1} \right)\pi ,\;k \in Z