JEE MATHEMATICS MCQ: TRIGONOMETRY RATIOS

1 Easy

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Analyzing +4 | -1

\pi < \alpha < \frac{{3\,\pi }}{2}

, then the expression

\sqrt {4{{\sin }^4}\alpha + {{\sin }^2}2\alpha } + 4{\cos ^2}\left( {\frac{\pi }{4} - \frac{\alpha }{2}} \right)

is equal to

View answer and explanation

Correct option: C

Option C (2) is correct because the expression simplifies to 2 using trigonometric identities and the given range of alpha.

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