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JEE PHYSICS MCQ: OSCILLATIONS

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Two simple harmonic motions are represented by

{y_1} = 4\sin \left( {4\pi t + \frac{\pi }{2}} \right)

and

\;{y_2} = 3\cos \left( {4\pi t} \right)

The resultant amplitude is

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Correct option: A

7

Option A (7) is correct because the two SHM equations are in phase, so the amplitudes add directly.

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