JEE MATHEMATICS MCQ: DIFFERENTIAL EQUATIONS

1 Easy

1 of 1

Application +4 | -1

If the function

y = {\sin ^{ - 1}}x

, then

\left( {1 - {x^2}} \right)\frac{{{d^2}y}}{{d{x^2}}}

is equal to

View answer and explanation

Correct option: C

x\frac{{dy}}{{dx}}

Option C (

x\frac{{dy}}{{dx}}

) is correct because it is the simplified form of the given expression after differentiating

y = {\sin ^{ - 1}}x

twice.

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\lim \limits_{{x \rightarrow \infty}} y(t)