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NEET UG CHEMISTRY MCQ: Equilibrium

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Application +4 | -1
How many mole of HCl\mathrm{HCl} are required to prepare one litre of buffer solution (containing NaCN+HCl\mathrm{NaCN} + \mathrm{HCl}) of pH  =  8.5\mathrm{pH}\;\mathrm{ = }\;8.5 using 0.01  g0.01\;g formula weight of NaCN(KHCN=4.1×10−10)\mathrm{NaCN}\left( {{K_{\mathrm{HCN}}} = 4.1 \times {{10}^{ - 10}}} \right)?
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Correct option: A
8.85×10−38.85 \times {10^{ - 3}}
Option A (8.85×10−38.85 \times {10^{ - 3}}) is correct because it represents the moles of HCl required to create the buffer solution with the specified pH, considering the equilibrium between HCN and CN-.

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