JEE MATHEMATICS MCQ: DIFFERENTIAL EQUATIONS

1 Easy

1 of 1

Application +4 | -1

\left(1+x^2\right) \frac{d y}{d x}=x(1-y), y(0)=\frac{4}{3}

, then the value of

y(\sqrt{8})+\frac{8}{9}

View answer and explanation

Correct option: B

Option B (2) is correct because solving the differential equation and substituting x =

\sqrt{8}

yields y(

\sqrt{8}

) = 10/3, and adding 8/9 gives 2.

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\lim \limits_{{x \rightarrow \infty}} y(t)