For the following cell with hydrogen electrodes at two different pressures ${p_1}{\kern 1pt} {\kern 1pt} {\rm{and}}{\kern 1pt} {\kern 1pt} {p_2}$ $\mathop {{\rm{Pt}}\left( {{{\rm{H}}_2}} \right)}\limits_{{p_1}} \left| {\mathop {{{\rm{H}}^ + }\left( {aq} \right)}\limits_{1{\rm{ }}M} } \right|\mathop {Pt\left( {{{\rm{H}}_2}} \right)}\limits_{{p_2}} $ emf is given by

$\frac{{RT}}{F}{\log _e}\frac{{{p_1}}}{{{p_2}}}$

$\frac{{RT}}{F}{\log _e}\frac{{{p_2}}}{{{p_1}}}$

$\frac{{RT}}{{2F}}{\log _e}\frac{{{p_2}}}{{{p_1}}}$

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NEET UG CHEMISTRY MCQ: ELECTRO CHEMISTRY

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Application +4 | -1

For the following cell with hydrogen electrodes at two different pressures

{p_1}{\kern 1pt} {\kern 1pt} \mathrm{and}{\kern 1pt} {\kern 1pt} {p_2}

\mathop {\mathrm{Pt}\left( {{\mathrm{H}_2}} \right)}\limits_{{p_1}} \left| {\mathop {{\mathrm{H}^ + }\left( {aq} \right)}\limits_{1\mathrm{ }M} } \right|\mathop {Pt\left( {{\mathrm{H}_2}} \right)}\limits_{{p_2}}

emf is given by

View answer and explanation

Correct option: B

\frac{{RT}}{{2F}}{\log _e}\frac{{{p_1}}}{{{p_2}}}

Option B (

\frac{{RT}}{{2F}}{\log _e}\frac{{{p_1}}}{{{p_2}}}

) is correct because the Nernst equation for this concentration cell involves the partial pressures of hydrogen and the number of electrons transferred is 1 per H+.

NEET UG CHEMISTRY MCQ: ELECTRO CHEMISTRY

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