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JEE MATHEMATICS MCQ: PROPERTIES OF TRIANGLES

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Application +4 | -1
In a Ξ”ABC\Delta ABC, (a+b+c)(b+cβˆ’a)(c+aβˆ’b)(a+bβˆ’c)4b2c2\frac{{\left( {a + b + c} \right)\left( {b + c - a} \right)\left( {c + a - b} \right)\left( {a + b - c} \right)}}{{4{b^2}{c^2}}} equals
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Correct option: C
sin⁑2A{\sin ^2}A
Option C (sin⁑2A{\sin ^2}A) is correct because the given expression can be simplified using the semi-perimeter formula and trigonometric identities to obtain sin⁑2A{\sin ^2}A.

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