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JEE MATHEMATICS MCQ: FUNCTIONS

1 Easy

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Application +4 | -1

Let

f:(2,3) \rightarrow(0,1)

be defined by

f(x)=x-[x]

then

f^{-1}(x)

equals

View answer and explanation

Correct option: D

x+2

Option D (

x+2

) is correct because in the interval (2,3),

[x] = 2

, so

f(x) = x-2

. Therefore,

f^{-1}(x) = x+2

.

More Questions from FUNCTIONS

Practice All Chapter MCQs →

f:(-\infty, 2] \longrightarrow(-\infty, 4]

f(x)=x(4-x)

f^{-1}(x)

is given by: If

g(f(x))=|\sin x|

f(g(x))=(\sin \sqrt{x})^2

f:\left( {2,\;3} \right) \to \left( {0,\;1} \right)

f\left( x \right) = x - \left[ x \right]

{f^{ - 1}}\left( x \right)

f: R \rightarrow R

f(x)=x^4

, Choose the correct answer. Which of the following functions are odd functions Let

f(x)=(x+1)^2-1(x \geq-1)

S=\left\{x: f(x)=f^{-1}(x)\right\}