Calculate work done required to increase the area of a rectangular film of liquid from $(4 \mathrm{~cm} \times 5 \mathrm{~cm})$ to $(5 \mathrm{~cm} \times 6 \mathrm{~cm})$. (surface tension of the liquid is $0.3 \mathrm{~N} / \mathrm{m}$ )

JEE PHYSICS MCQ: MECHANICAL PROPERTIES OF FLUIDS

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Application +4 | -1

Calculate work done required to increase the area of a rectangular film of liquid from

(4 \mathrm{~cm} \times 5 \mathrm{~cm})

(5 \mathrm{~cm} \times 6 \mathrm{~cm})

. (surface tension of the liquid is

0.3 \mathrm{~N} / \mathrm{m}

)

View answer and explanation

Correct option: C

6 \times 10^{-4} \mathrm{~J}

Option C (

6 \times 10^{-4} \mathrm{~J}

) is correct because it is calculated using the formula for work done in increasing the surface area of a liquid film.

Practice All Chapter MCQs →

80 \mathrm{~kg}

20 \mathrm{~cm}

0.5 \mathrm{~cm}

0.1 \mathrm{~cm}

15 \mathrm{~m} / \mathrm{s}

5 \mathrm{~m}

=10^{-2}

m_1

d_1

d_2

m_2