JEE PHYSICS MCQ: THERMAL PROPERTIES OF MATTER

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Application +4 | -1

The temperature at the two ends

A

and

B

of a rod of length

25 \mathrm{~cm}

and circular cross-section are

100^{\circ} \mathrm{C}

and

0^{\circ} \mathrm{C}

, respectively. In the steady state, the temperature at a point

10 \mathrm{~cm}

from the end

B

is (Ignore loss of heat from curved surface of the rod)

View answer and explanation

Correct option: D

40^{\circ} \mathrm{C}

Option D (

40^{\circ} \mathrm{C}

) is correct because the temperature gradient is linear along the rod in steady state, allowing for a direct proportion calculation.

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