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JEE MATHEMATICS MCQ: COMPLEX NUMBERS

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Application +4 | -1
If Z1=1a+i,a≠0Z_1=\frac{1}{a+i}, a \neq 0 and Z2=11+bib≠0Z_2=\frac{1}{1+\mathrm{bi}} \quad b \neq 0 such that Z1=Zˉ2Z_1=\bar{Z}_2 then
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Correct option: C
a=1, b=−1\mathrm{a}=1, \mathrm{~b}=-1
Option C (a=1, b=-1) is correct because it satisfies the condition Z1 = conjugate(Z2) by equating real and imaginary parts.

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