The oxidation state of Ni in ${\rm{Ni}}{\left( {{\rm{CO}}} \right)_4}$ is :

NEET UG CHEMISTRY MCQ: REDOX REACTIONS

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The oxidation state of Ni in

\mathrm{Ni}{\left( {\mathrm{CO}} \right)_4}

is :

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Correct option: A

Zero

Option A (Zero) is correct because carbonyl (CO) is a neutral ligand, so the oxidation state of Ni in the complex is zero.

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{I_2}

\mathrm{MnO}_4^ - + {\mathrm{C}_2}\mathrm{O}_4^{2 - } + {\mathrm{H}^ + } \to \mathrm{M}{\mathrm{n}^{2 + }} + \mathrm{C}{\mathrm{O}_2} + {\mathrm{H}_2}\mathrm{O}

\mathrm{MnO}_4^ -

{\mathrm{C}_2}\mathrm{O}_4^{2 - }

{\mathrm{H}^ + }