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JEE MATHEMATICS MCQ: PROPERTIES OF TRIANGLES

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In a △ABC,R=\triangle A B C, R= circumradius and r=r= inradius. The value of acos⁡A+bcos⁡B+ccos⁡Ca+b+c\frac{a \cos A+b \cos B+c \cos C}{a+b+c} is equal to
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Correct option: C
rR\frac{r}{R}
Option C (r/Rr/R) is correct because by using trigonometric identities and the definitions of inradius and circumradius, the given expression simplifies to r/Rr/R.

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