JEE PHYSICS MCQ: SYSTEM OF PARTICLES

1 Easy

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Application +4 | -1

A thick straight wire of length

4\pi \,m\,

is fixed at its midpoint and the bent in the form of a circle. The shift in its centre of mass is

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Correct option: C

2 m

Option C (2 m) is correct because the shift in the center of mass is equal to the radius of the circle formed by bending the wire.

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\mathrm{AB}

\mathrm{L}

\mu(x)=a+\frac{b x}{L}

x

\mathrm{A}

\mathrm{CM}

\left(\frac{7}{12}\right) \mathrm{L}

\mathrm{A}

\mathrm{b}

1.0 \mathrm{~g}

8 \mathrm{~cm}

\omega = {t^4} + 2{t^3}

t = 1\,sec

\left( {rad\,{s^{ - 2}}} \right)