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JEE PHYSICS MCQ: THERMAL PROPERTIES OF MATTER

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The temperature gradient in a rod of 0.5m0.5m long is 800C/m{80^0}C/m . If the temperature of hotter end of the rod is 300C{30^0}C, then the temperature of the cooler end is
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Correct option: B
−100C- {10^0}C
Option B (−100C- {10^0}C) is correct because it is calculated by using the temperature gradient formula and solving for the cooler end temperature.

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