JEE MATHEMATICS MCQ: INDEFINITE INTEGRATION

1 Easy

1 of 1

Application +4 | -1

The value of

\int \frac{1}{\sqrt{\sin ^3 x \cos ^5 x}} d x

, is

View answer and explanation

Correct option: A

\frac{-2}{\sqrt{\tan x}}+\frac{2}{3}(\tan x)^{3 / 2}+C

Option A (

\frac{{-2}}{{\sqrt{{\tan x}}}}+\frac{{2}}{{3}}(\tan x)^{{3 / 2}}+C

) is correct because the integral is solved by manipulating the integrand and using substitution.

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\int \sin ^5 x \cos ^4 x d x=

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\int \frac{1-7 \cos ^2 x}{\sin ^7 x \cos ^2 x} d x=\frac{f(x)}{\sin ^7 x}+C

\int {e}^{{x}^2}\left(2-\frac{1}{{x}^2}\right) {de}={e}^{{x}^2} {f}({x})+{C}

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{C}

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