JEE MATHEMATICS MCQ: STRAIGHT LINES

1 Easy

1 of 1

Remembering +4 | -1

Consider the following statements.

I. The distance between two points

\left(x_1, y_1\right)

and

\left(x_2, y_2\right)

is given by

\sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}

II. The coordinates of the mid-point of the line segment joining the points

\left(x_1, y_1\right)

and

\left(x_2, y_2\right)

\left(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2}\right)

Choose the correct option.

View answer and explanation

Correct option: C

Both are true

Option C (Both are true) is correct because both the distance formula and the midpoint formula are stated accurately.

More Questions from STRAIGHT LINES

Practice All Chapter MCQs →

x-3 y=p, a x+2 y=q

a x+y=r

\left\{ {a{t_1}{t_2},\;a\left( {{t_1} + {t_2})\} ,\{ a{t_2}{t_3},a({t_2} + {t_3}} \right)} \right\},\;\left\{ {a{t_3}{t_1},\;a\left( {{t_3} + {t_1}} \right)} \right\}

y = 2\;x + 4

6x = 3y + 5

{x^2} + {y^2} + 2xy - 8ax - 8ay - 9{a^2} = 0

(3,8)

x+3 y=7

\left( {{x^2} + 7xy + 2{y^2}} \right)\left( {y - 1} \right) = 0