JEE MATHEMATICS MCQ: COMPLEX NUMBERS

1 Easy

1 of 1

Application +4 | -1

\frac{{{{\left( {\cos \theta + i\sin \theta } \right)}^4}}}{{{{\left( {\sin \theta + i\cos \theta } \right)}^5}}}

is equal to

View answer and explanation

Correct option: D

\sin 9\theta - i\cos 9\theta

Option D (

\sin 9\theta - i\cos 9\theta

) is correct because by applying De Moivre's theorem and simplifying, the expression reduces to the given form.

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