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JEE MATHEMATICS MCQ: INDEFINITE INTEGRATION

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Analyzing +4 | -1
Let f(x)=∫x2(1+x2)(1+1+x2)dxf(x)=\int \frac{x^2}{\left(1+x^2\right)\left(1+\sqrt{1+x^2}\right)} d x and f(0)=0f(0)=0. Then f(1)f(1) is equal to
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Correct option: B
log⁡e(1+2)−π4\log _e(1+\sqrt{2})-\frac{\pi}{4}
Option B is correct because after substituting x=tan⁡θx = \tan \theta and simplifying, the integral evaluates to log⁡e(1+2)−π4\log _e(1+\sqrt{2})-\frac{\pi}{4}.

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