Question

Let $g\left( x \right) = \cos {x^2},f\left( x \right) = \sqrt x $ and $\alpha ,\beta \left( {\alpha < \beta } \right)$ be the roots of the quadratic equation $18{x^2} - 9\pi x + {\pi ^2} = 0$ Then, the area (in sq units) bounded by the curve $y = \left( {gof} \right)\left( x \right)$ and the lines $x = \alpha ,\,x = \beta $ and $y=0$ is

Accepted Answer

$\frac{1}{2}\left( {\sqrt 3 - 1} \right)$

Answer

$\frac{1}{2}\left( {\sqrt 3 + 1} \right)$

Answer

$\frac{1}{2}\left( {\sqrt 3 - \sqrt 2 } \right)$

Answer

$\frac{1}{2}\left( {\sqrt 2 - 1} \right)$

JEE MATHEMATICS MCQ: FUNCTIONS

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