JEE MATHEMATICS MCQ: TRIGONOMETRY RATIOS

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Application +4 | -1

\pi < \alpha < \frac{3 \pi}{2}

, then

\sqrt{\frac{1-\cos \alpha}{1+\cos \alpha}}+\sqrt{\frac{1+\cos \alpha}{1-\cos \alpha}}=

View answer and explanation

Correct option: B

-\frac{2}{\sin \alpha}

Option B (

-\frac{{2}}{{\sin \alpha}}

) is correct because, within the given range for alpha, the expression simplifies to this value considering the sign of sine in that quadrant.

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