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JEE MATHEMATICS MCQ: INDEFINITE INTEGRATION

1 Easy
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Application +4 | -1
∫tan⁡32xsec⁡2xdx=\int \tan ^3 2 x \sec 2 x d x=
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Correct option: B
16[sec⁡32x−3sec⁡2x]\frac{1}{6}\left[\sec ^3 2 x-3 \sec 2 x\right]
Option B (16[sec⁡32x−3sec⁡2x]\frac{1}{6}[\sec ^3 2 x-3 \sec 2 x]) is correct because it is the result of substituting sec⁡2x=t\sec 2x = t and integrating the resulting polynomial.

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