NEET UG CHEMISTRY MCQ: ELECTRO CHEMISTRY

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Ionic mobility of

\mathrm{A}{\mathrm{g}^ + }

is
(

{\lambda _{\mathrm{A}{\mathrm{g}^ + }}} = 5 \times {10^{ - 1}}{\kern 1pt} {\kern 1pt}{\Omega ^{ - 1}}{\kern 1pt} {\kern 1pt}\mathrm{c}{\mathrm{m}^2}{\kern 1pt} {\kern 1pt}\mathrm{equi}{\mathrm{v}^{ - 1}}

)

View answer and explanation

Correct option: A

5.2 \times {10^{ - 9}}

Option A is correct because ionic mobility is calculated using the formula: ionic mobility = (ionic conductance) / (Faraday's constant), which gives approximately 5.2 × 10^-9 m² V^-1 s^-1.

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