JEE MATHEMATICS MCQ: INDEFINITE INTEGRATION

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Application +4 | -1

\int \frac{1}{a^2 \sin ^2 x+b^2 \cos ^2 x} d x=\frac{1}{12} \tan ^{-1}(3 \tan x)+

constant, then the maximum value of

a \sin x+b \cos x

, is :

View answer and explanation

Correct option: A

\sqrt{40}

Option A (

\sqrt{40}

) is correct because after solving the integral and comparing coefficients, we find a=6 and b=2, leading to the maximum value of

a \sin x + b \cos x

\sqrt{40}

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