JEE MATHEMATICS MCQ: COMPLEX NUMBERS

1 Medium

1 of 1

Analyzing +4 | -1

a,\;b,\;c \ne 0

and belongs to the set

\left\{ {0,\;1,2,\;3,\; \ldots \ldots ..,\;9} \right\}

,
Then

{\log _{10}}\left( {\frac{{a + 10b + {{10}^2}c}}{{{{10}^{ - 4}}a + {{10}^{ - 3}}b + {{10}^{ - 2}}c}}} \right)

is equal to

View answer and explanation

Correct option: D

Option D (4) is correct because the expression simplifies to

{\log _{10}}{10^4}

, which equals 4.

More Questions from COMPLEX NUMBERS

Practice All Chapter MCQs →

{\left| {1 - i} \right|^x} = {2^x}

|z|=1

z \neq \pm 1

z, \frac{z}{1-z^2}

\left|z_r-r\right| \leq r, \forall r=1,2,3, \ldots, n

\left|\sum\limits_{r=1}^n z_r\right|

(z+a b)^3=a^3

a \neq 0

\alpha, \beta

\gamma

|\alpha-\beta|

{z^2} + {\left| z \right|^2} = 0,

z \in C

2x = - 1 + \sqrt 3 i

{\left( {1 - {x^2} + x} \right)^6} - {\left( {1 - x + {x^2}} \right)^6}