JEE MATHEMATICS MCQ: FUNCTIONS

1 Easy

1 of 1

Analyzing +4 | -1

The function

f\left( x \right) = {\log _{10}}\left( {x + \sqrt {{x^2} + 1} } \right)

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Correct option: B

An odd function

Option B (An odd function) is correct because it satisfies the condition f(-x) = -f(x), indicating odd symmetry.

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S=\left\{x: f(x)=f^{-1}(x)\right\}