JEE MATHEMATICS MCQ: STRAIGHT LINES

1 Easy

1 of 1

Application +4 | -1

A straight line

L

through the point

(3,-2)

is inclined at an angle of

60^{\circ}

to the line

\sqrt{3} x+y=1

. If L also intersects the

x

-axis, then the equation of

L

, is

View answer and explanation

Correct option: B

y-\sqrt{3} x+2+3 \sqrt{3}=0

Option B (

y-\sqrt{3} x+2+3 \sqrt{3}=0

) is correct because it represents a line passing through (3, -2) and inclined at 60 degrees to the given line, and it also intersects the x-axis.

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x-3 y=p, a x+2 y=q

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\left\{ {a{t_1}{t_2},\;a\left( {{t_1} + {t_2})\} ,\{ a{t_2}{t_3},a({t_2} + {t_3}} \right)} \right\},\;\left\{ {a{t_3}{t_1},\;a\left( {{t_3} + {t_1}} \right)} \right\}

y = 2\;x + 4

6x = 3y + 5

{x^2} + {y^2} + 2xy - 8ax - 8ay - 9{a^2} = 0

(3,8)

x+3 y=7

\left( {{x^2} + 7xy + 2{y^2}} \right)\left( {y - 1} \right) = 0