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JEE MATHEMATICS MCQ: FUNCTIONS

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Analyzing +4 | -1
Consider a function f:N→Rf: N \rightarrow R, satisfying f(1)+2f(2)+3f(3)+….xf(x)=x(x+1)f(x);x≥2f(1)+2 f(2)+3 f(3)+\ldots . x f(x)=x(x+1) f(x) ; x \geq 2 with f(1)=1f(1)=1. Then 1f(2022)+1f(2028)\frac{1}{f(2022)}+\frac{1}{f(2028)} is equal to
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Correct option: C
8100
Option C (8100) is correct because the value is obtained by correctly solving the recurrence relation and substituting the value in the required expression.

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