JEE MATHEMATICS MCQ: CIRCLES

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Analyzing +4 | -1

The set of all values of

a^{2}

for which the line

x+y=0

bisects two distinct chords drawn from a point

P\left(\frac{1+a}{2}, \frac{1-a}{2}\right)

on the circle

2 x^{2}+2 y^{2}-

(1+a) x-(1-a) y=0

is equal to

View answer and explanation

Correct option: A

(8, \infty)

Option A (

(8, \infty)

) is correct because the condition for the line to bisect two distinct chords leads to the inequality

a^2 > 8

More Questions from CIRCLES

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{\left( {{\alpha ^2}{x^2} - 2\alpha \mathrm{ }x + 1} \right)^{51}},

x

\left( {\alpha ,2{\alpha ^2}} \right)

{x^2} + {y^2} = 4,

{x^2} + {y^2} - 2x + 4y - 4 = 0

{x^2} + {y^2} = {a^2}

\left( {{x_1},{y_1}} \right)

\quad \alpha, \beta

\gamma

P, Q

x^2+y^2=1

A

(-1,0)

A P, A Q

A R

G P

\cos \alpha / 2, \cos \beta / 2

\cos \gamma / 2

x+y=6

x+2 y=4

x+y=5

x-y=1

9 \pi