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JEE MATHEMATICS MCQ: DIFFERENTIAL EQUATIONS

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Let f(x)f(x) be differentiable on the interval (0,∞)(0, \infty) such that f(1)=1f(1)=1, and lim⁡t→xt2f(x)−x2f(t)t−x=1\lim\limits _{t \rightarrow x} \frac{t^2 f(x)-x^2 f(t)}{t-x}=1 for each x>0x>0. Then f(x)f(x) is
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Correct option: A
13x+23x2\frac{1}{3 x}+\frac{2}{3} x^2
Option A is correct because it satisfies the given limit condition and the initial condition f(1)=1 after solving the differential equation.

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