Question

If $\frac{x}{a}\cos \,\,\alpha + \frac{y}{b}\,\,\sin \alpha = 1,\frac{x}{a}\cos \beta + \frac{y}{b}\,\,\sin \beta = 1$ and $\frac{{\cos \alpha \,\,\cos \beta }}{{{a^2}}} + \frac{{\sin \alpha \,\,\sin \beta }}{{{b^2}}} = 0$, then

Accepted Answer

$	an \alpha \,\,	an \beta = \frac{{{b^2}\left( {{x^2} - {a^2}} ight)}}{{{a^2}\left( {{y^2} - {b^2}} ight)}}\;\,{m{and}}\,\;{x^2} + {y^2} = {a^2} - {b^2}$

Answer

$	an \alpha \,\,	an \beta = \frac{{{a^2}}}{{{b^2}}}$

Answer

${x^2} + {y^2} = {a^2} - {b^2}$

Answer

None of these

JEE MATHEMATICS MCQ: TRIGONOMETRY RATIOS

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