If $f(x)=3 x+10, g(x)=x^2-1$, then $(f \circ g)^{-1}$ is equal to

$\left(\frac{x-3}{7}\right)^{1 / 2}$

$\left(\frac{x+3}{7}\right)^{1 / 2}$

JEE MATHEMATICS MCQ: FUNCTIONS

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Application +4 | -1

f(x)=3 x+10, g(x)=x^2-1

, then

(f \circ g)^{-1}

is equal to

View answer and explanation

Correct option: A

\left(\frac{x-7}{3}\right)^{1 / 2}

Option A (

\left( \frac{{x-7}}{{3}} \right)^{{1 / 2}}

) is correct because

(f \circ g)(x) = 3x^2 + 7

, and its inverse is found by solving for

x

in terms of

y

, resulting in

x = \sqrt{{\frac{{y-7}}{{3}}}}

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