NEET UG CHEMISTRY MCQ: THERMODYNAMICS

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\begin{aligned} & \mathrm{HA}+\mathrm{OH}^{-} \rightarrow \mathrm{H}_2 \mathrm{O}+\mathrm{A}^{-}+\mathrm{q}_1 \mathrm{~kJ} \\ & \mathrm{H}^{+}+\mathrm{OH}^{-} \rightarrow \mathrm{H}_2 \mathrm{O}+\mathrm{q}_2 \mathrm{~kJ} \end{aligned}

The enthalpy of ionisation of

\mathrm{HA}

View answer and explanation

Correct option: C

\left(\mathrm{q_2-q}_1\right)

Option C (

(q_2-q_1)

) is correct because the enthalpy of ionization is the difference between the heat released during the neutralization of a strong acid and the heat released during the neutralization of the weak acid.

More Questions from THERMODYNAMICS

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The internal energy of one mole of a gas is: An ideal gas is allowed to expand both reversibly and irreversibly in an isolated system. If

{T_i}

is the initial temperature and

{T_f}

is the final temperature, which of the following statements is correct? For which of the process, ∆S is negative? The work done by a weightless piston in causing an expansion ∆V (at constant temperature), when the opposing pressure, P is variable, is given by: Assertion :- At constant pressure of the change

\mathrm{H}_2 \mathrm{O}(\mathrm{s}) \rightarrow \mathrm{H}_2 \mathrm{O}(\mathrm{g})

work done is negative.

Reason :- During phase transition work done is always negative. For the reaction,

\mathrm{X}_2 \mathrm{O_4(l}) \longrightarrow 2 \mathrm{XO}_2(\mathrm{g}), \Delta U=2.1 \mathrm{~kcal}, \Delta S=20 \mathrm{~cal} \mathrm{~K}^{-1}

300 \mathrm{~K}

. Hence,

\Delta G