The oxidation number of $\mathrm{Fe}$ in $[\mathrm{Fe}(\mathrm{CN})_6]^{4-}, \mathrm{Co}$ in $\left[\mathrm{Co}(\mathrm{NH}_3)_3\left(\mathrm{NO}_2\right)_3\right]$ and $\mathrm{Ni}$ in $[\mathrm{Ni}(\mathrm{CO})_4]$ are respectively

NEET UG CHEMISTRY MCQ: CO-ORDINATION COMPOUNDS

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Application +4 | -1

The oxidation number of

\mathrm{Fe}

[\mathrm{Fe}(\mathrm{CN})_6]^{4-}, \mathrm{Co}

\left[\mathrm{Co}(\mathrm{NH}_3)_3\left(\mathrm{NO}_2\right)_3\right]

and

\mathrm{Ni}

[\mathrm{Ni}(\mathrm{CO})_4]

are respectively

View answer and explanation

Correct option: A

+2,+3,0

Option A (+2, +3, 0) is correct because it accurately calculates the oxidation states of Fe, Co, and Ni in the given complexes.

Practice All Chapter MCQs →

\left[ {\mathrm{PtC}{\mathrm{l}_2}{{\left( {\mathrm{N}{\mathrm{H}_3}} \right)}_4}} \right]\mathrm{B}{\mathrm{r}_2}\mathrm{\;and\;}\left[ {\mathrm{PtB}{\mathrm{r}_2}{{\left( {\mathrm{N}{\mathrm{H}_3}} \right)}_4}} \right]\mathrm{C}{\mathrm{l}_2}\mathrm{\;}

\left[\mathrm{Cr}(\mathrm{Ox})_{2} \mathrm{ClBr}\right]^{3-}

\text{ox =}

x

{\left[ {\mathrm{Ni}{{\left( {\mathrm{CN}} \right)}_4}} \right]^x}

\mathrm{M}{\mathrm{n}^{2 + }}

\mathrm{CuS}{\mathrm{O}_4}

{\mathrm{K}_2}\left[ {\mathrm{Ni}{{\left( {\mathrm{CN}} \right)}_4}} \right]