JEE MATHEMATICS MCQ: DCS AND DRS

1 Easy

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Analyzing +4 | -1

The line

\frac{x+6}{5}=\frac{y+10}{3}=\frac{z+14}{8}

is the hypotenuse of an isosceles right angled triangle whose opposite vertex is

(7,2,4)

. Then which of the following is not the side of the triangle ?

View answer and explanation

Correct option: B

\frac{x-7}{3}=\frac{y-2}{6}=\frac{z-4}{2}

Option B (

\frac{x-7}{3}=\frac{y-2}{6}=\frac{z-4}{2}

) is correct because this line is not a side of the isosceles right-angled triangle.

More Questions from DCS AND DRS

Practice All Chapter MCQs →

\frac{2-x}{3}=\frac{3 y-2}{4 \lambda+1}=4-z

\frac{x+3}{3 \mu}=\frac{1-2 y}{6}=\frac{5-z}{7},

4 \lambda+9 \mu

\frac{x}{2}=\frac{y}{2}=\frac{z}{1}

\frac{x+2}{-1}=\frac{y-4}{8}=\frac{z-5}{4}

4 {~m}

2 {~kg}

10 {~kg}

45^{\circ}

60^{\circ}

X

Y

Z

\mathrm{AB}

-2 / \sqrt{17}

3 / \sqrt{17},-2 / \sqrt{17}

\mathrm{AB}=\sqrt{17}

\mathrm{A}

(3,-6,10)

\mathrm{B}

A B

45^{\circ}

120^{\circ}

X

Y

A B

\theta

Z

\theta