Question

The integral $\int {\frac{{dx}}{{{{\left( {x + 4} \right)}^{8/7}}{{\left( {x - 3} \right)}^{6/7}}}}} $ is equal to (where $C$ is a constant of integration)

Accepted Answer

${\left( {\frac{{x - 3}}{{x + 4}}} \right)^{1/7}} + C$

Answer

$ - {\left( {\frac{{x - 3}}{{x + 4}}} \right)^{ - 1/7}} + C$

Answer

$\frac{1}{2}{\left( {\frac{{x - 3}}{{x + 4}}} \right)^{3/7}} + C$

Answer

$ - \frac{1}{{13}}{\left( {\frac{{x - 3}}{{x + 4}}} \right)^{ - 13/7}} + C$

JEE MATHEMATICS MCQ: INDEFINITE INTEGRATION

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