O.N. of $\mathrm{V}$ in $\mathrm{Rb}_4 \mathrm{Na}\left[\mathrm{HV}_{10} \mathrm{O}_{28}\right]$ is-

NEET UG CHEMISTRY MCQ: REDOX REACTIONS

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Application +4 | -1

O.N. of

\mathrm{V}

\mathrm{Rb}_4 \mathrm{Na}\left[\mathrm{HV}_{10} \mathrm{O}_{28}\right]

is-

View answer and explanation

Correct option: B

+5

Option B (+5) is correct because Rb has +1, Na has +1, H has +1, and O has -2, balancing the charge of the complex ion.

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{I_2}

\mathrm{MnO}_4^ - + {\mathrm{C}_2}\mathrm{O}_4^{2 - } + {\mathrm{H}^ + } \to \mathrm{M}{\mathrm{n}^{2 + }} + \mathrm{C}{\mathrm{O}_2} + {\mathrm{H}_2}\mathrm{O}

\mathrm{MnO}_4^ -

{\mathrm{C}_2}\mathrm{O}_4^{2 - }

{\mathrm{H}^ + }