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JEE MATHEMATICS MCQ: MATHEMATICAL REASONING

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Analyzing +4 | -1
Among the statements

(S1):(p⇒q)∨((∼p)∧q)(\mathrm{S} 1):(p \Rightarrow q) \vee((\sim p) \wedge q) is a tautology

(S2):(q⇒p)⇒((∼p)∧q)(\mathrm{S} 2):(q \Rightarrow p) \Rightarrow((\sim p) \wedge q) is a contradiction
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Correct option: A
Neither (S1) and (S2) is True
Option A (Neither (S1) and (S2) is True) is correct because both statements are neither tautologies nor contradictions after simplification.

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