JEE MATHEMATICS MCQ: TRIGONOMETRY RATIOS

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Application +4 | -1

One root of the equation

\cos \,\,\theta - \theta + \frac{1}{2} = 0

lies in the interval

View answer and explanation

Correct option: A

\left( {0,\,\;\pi /2} \right)

Option A (

\left( {0,\;\pi /2} \right)

) is correct because the function changes sign within this interval, indicating the presence of a root.

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\tan \alpha=\frac{p}{q}

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\triangle A B C

C

{\sin ^6}\,\,\theta + {\cos ^6}\,\,\theta + 3{\sin ^2}\,\,\theta \,\,{\cos ^2}\,\,\theta

\sin ^2 \frac{A}{2}+\sin ^2 \frac{B}{2}+\sin ^2 \frac{C}{2}=

\sin ^2(A / 2)+\sin ^2(B / 2)-\sin ^2(C / 2)=