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JEE PHYSICS MCQ: CURRENT ELECTRICITY

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If the free electron density be n and relaxation time be τ\tau, the electrical conductivity of a conductor may be expressed as
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Correct option: B
ne2τme\frac{{n{e^2}\tau }}{{{m_e}}}
Option B (ne2τme\frac{{n{e^2}\tau }}{{{m_e}}}) is correct because the electrical conductivity is directly proportional to the free electron density, the square of the electron charge, and the relaxation time, and inversely proportional to the electron mass.

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