JEE PHYSICS MCQ: CURRENT ELECTRICITY

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Application +4 | -1

The charge flowing in a conductor changes with time as

Q(t)=\alpha t-\beta t^2+\gamma t^3

. Where

\alpha, \beta

and

\gamma

are constants. Minimum value of current is

View answer and explanation

Correct option: B

\alpha-\frac{\beta^2}{3 \gamma}

Option B (

\alpha-\frac{\beta^2}{3 \gamma}

) is correct because it is the minimum value of the current obtained by differentiating the current equation with respect to time and setting it to zero.

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