JEE MATHEMATICS MCQ: STRAIGHT LINES

1 Easy

1 of 1

Application +4 | -1

A(3,-1), B(1,3), C(2,4)

are vertices of

\triangle A B C

. If

D

is the centroid of

\triangle A B C

and

P

is the point of intersection of lines

x+3 y-1=0

and

3 x-y+1=0

, then which of the following points lies on the line joining

D

and

P

View answer and explanation

Correct option: B

(-9,-6)

Option B ((-9,-6)) is correct because the point lies on the line formed by the centroid and the intersection point of the given lines.

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x-3 y=p, a x+2 y=q

a x+y=r

\left\{ {a{t_1}{t_2},\;a\left( {{t_1} + {t_2})\} ,\{ a{t_2}{t_3},a({t_2} + {t_3}} \right)} \right\},\;\left\{ {a{t_3}{t_1},\;a\left( {{t_3} + {t_1}} \right)} \right\}

y = 2\;x + 4

6x = 3y + 5

{x^2} + {y^2} + 2xy - 8ax - 8ay - 9{a^2} = 0

(3,8)

x+3 y=7

\left( {{x^2} + 7xy + 2{y^2}} \right)\left( {y - 1} \right) = 0