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JEE MATHEMATICS MCQ: FUNCTIONS

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If f(x+2y,x,x−2y)=xyf\left( {x + 2y,x,x - 2y} \right) = xy, then f(x,  y)f\left( {x,\;y} \right) equals
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Correct option: A
x2−y28\frac{{{x^2} - {y^2}}}{8}
Option A (x2−y28\frac{{{x^2} - {y^2}}}{8}) is correct because by substituting x+2y=ux + 2y = u and x−2y=vx - 2y = v, we can express f(u,v)f(u, v) in terms of uu and vv, leading to the given expression.

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