JEE PHYSICS MCQ: THERMODYNAMICS

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Application +4 | -1

In a heat engine, the temperature of the source and sink are

500 \mathrm{~K}

and

375 \mathrm{~K}

. If the engine consumes

5 \times 10^5 \mathrm{~J}

per cycle, the work done per cycle is:

View answer and explanation

Correct option: C

1.25 \times 10^5 \mathrm{~J}

Option C (

1.25 \times 10^5 \mathrm{~J}

) is correct because it is calculated by finding the efficiency of the heat engine and multiplying it by the heat consumed per cycle.

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