JEE MATHEMATICS MCQ: COMPLEX NUMBERS

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Application +4 | -1

\frac{3}{2+\cos \theta+i \sin \theta}=a+i b

, then

(a-2)^2+b^2

is equal to

View answer and explanation

Correct option: B

The value of

(a-2)^2 + b^2

is 1 because it is obtained by manipulating the given expression and using trigonometric identities.

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