Skip to main content
Back to GRAVITATION

JEE PHYSICS MCQ: GRAVITATION

1 Medium
1 of 1
Analyzing +4 | -1
A system consists of N{N} identical particles of mass m{m} placed rigidly on the vertices of a regular polygon with each side of length ℓ\ell. If K1{K}_1 be the kinetic energy imparted to one of the particles so that it just escapes the gravitational pull of the system and there after kinetic energy K2{K}_2 is given by to the adjacent particle to escape, then the difference (K1−K2)\left({K}_1-{K}_2\right) is
View answer and explanation
Correct option: D
Gm2a\frac{G m^2}{a}
Option D (Gm2a\frac{G m^2}{a}) is correct because the difference in kinetic energies is equal to the gravitational potential energy difference between the last particle's interaction.

More Questions from GRAVITATION

Practice All Chapter MCQs →
Type at least 2 characters or jump directly:
🔓

Save your learning progress

Sign in with a free account to save your practice answers and quiz results, then return to them when you revise.