JEE MATHEMATICS MCQ: FUNCTIONS

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Analyzing +4 | -1

The domain of the function

f\left( x \right) = \frac{{{{\cos }^{ - 1}}x}}{{\left[ x \right]}}

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Correct option: A

\left[ { - 1,\;0} \right) \cup \left\{ 1 \right\}

Option A (

\left[ { - 1,\;0} \right) \cup \left\{ 1 \right\}

) is correct because it considers the domain of the inverse cosine function and the restriction that the denominator of the fraction cannot be zero.

More Questions from FUNCTIONS

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f:(-\infty, 2] \longrightarrow(-\infty, 4]

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f:\left( {2,\;3} \right) \to \left( {0,\;1} \right)

f\left( x \right) = x - \left[ x \right]

{f^{ - 1}}\left( x \right)

f: R \rightarrow R

f(x)=x^4

f(x)=(x+1)^2-1(x \geq-1)

S=\left\{x: f(x)=f^{-1}(x)\right\}