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JEE MATHEMATICS MCQ: TRIGONOMETRY RATIOS

1 Easy
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Application +4 | -1
In a △ABC,∠A=π/2\triangle A B C, \angle A=\pi / 2, then cos⁡2B+cos⁡2C\cos ^2 B+\cos ^2 C equals.
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Correct option: C
1
Option C (1) is correct because in a right-angled triangle, ∠A=π2\angle A = \frac{\pi}{2}, so B+C=π2B + C = \frac{\pi}{2}. Therefore, cos⁡B=sin⁡C\cos B = \sin C, and cos⁡2B+cos⁡2C=sin⁡2C+cos⁡2C=1\cos^2 B + \cos^2 C = \sin^2 C + \cos^2 C = 1.

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