The standard potential at ${25^ \circ }C$ for the following half-reactions are given against them ${\rm{Z}}{{\rm{n}}^{2 + }} + 2{e^ - } \to {\rm{Zn}},{E^ \circ } = - 0.762{\rm{V}}$ ${\rm{M}}{{\rm{g}}^{2 + }} + 2{e^ - } \to {\rm{Mg}},{E^ \circ } = - 2.37{\rm{V}}$ When zinc dust is added to the solution of ${\rm{MgC}}{{\rm{l}}_2}$,

${\rm{ZnC}}{{\rm{l}}_2}$ is formed

NEET UG CHEMISTRY MCQ: ELECTRO CHEMISTRY

1 Hard

1 of 1

Application +4 | -1

The standard potential at

{25^ \circ }C

for the following half-reactions are given against them

\mathrm{Z}{\mathrm{n}^{2 + }} + 2{e^ - } \to \mathrm{Zn},{E^ \circ } = - 0.762\mathrm{V}

\mathrm{M}{\mathrm{g}^{2 + }} + 2{e^ - } \to \mathrm{Mg},{E^ \circ } = - 2.37\mathrm{V}

When zinc dust is added to the solution of

\mathrm{MgC}{\mathrm{l}_2}

View answer and explanation

Correct option: D

No reaction takes place

Option D (No reaction takes place) is correct because zinc has a higher reduction potential than magnesium, so it cannot reduce Mg2+ to Mg.